Armstrong Number in Python

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A number is called an Armstrong number on the off chance that the amount of blocks of digits of a number is equivalent to the actual number. In the beneath C program, we are checking regardless of whether the info number is Armstrong.

Armstrong number is a number that is equivalent to the amount of 3D squares of its digits. For instance 0, 1, 153, 370, 371, and 407 are the Armstrong numbers.

We should attempt to comprehend the reason why 153 is an Armstrong number.

153 = (1*1*1)+(5*5*5)+(3*3*3)
where:
(1*1*1)=1
(5*5*5)=125
(3*3*3)=27
So:
1+125+27=153

What is Armstrong Number?

A three-digit number can be supposed to be an Armstrong number when the amount of all its singular digits blocks is equivalent to the actual number.

Armstrong Number in Python using 3 digits

At first, We can give the 3 digits of contribution to check regardless of whether the given info number is an Armstrong Number in the beneath program.

# Python program to check if the number is an Armstrong number or not

# take input from the user
num = int(input("Enter a number: "))

# initialize sum
sum = 0

# find the sum of the cube of each digit
temp = num
while temp > 0:
   digit = temp % 10
   sum += digit ** 3
   temp //= 10

# display the result
if num == sum:
   print(num,"is an Armstrong number")
else:
   print(num,"is not an Armstrong number")

Output

Two types of inputs are given below to clear your doubts.

Enter a number: 154
154 is not an Armstrong number

Enter a number: 153
153 is an Armstrong number

Armstrong Number in Python using n digits

num = 1634

# Changed num variable to string, 
# and calculated the length (number of digits)
order = len(str(num))

# initialize sum
sum = 0

# find the sum of the cube of each digit
temp = num
while temp > 0:
   digit = temp % 10
   sum += digit ** order
   temp //= 10

# display the result
if num == sum:
   print(num,"is an Armstrong number")
else:
   print(num,"is not an Armstrong number")

Conclusion

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